An industrial bandsaw of total length $L = 10.4$ $\displaystyle{m}$ and width $w = 0.229$ $\displaystyle{m}$ is tightened between two wheels, each of diameter $D = 1.6$ $\displaystyle{m}$. The total force between the wheels $F = 43$ $\displaystyle{kN}$. For saw-blade steel, $E = 200$ $GPa$, $\nu = 0.3$. What thickness would you choose to minimize the tensile stress within the saw-blade? $t=$$mm$