A bolted assembly consists of a steel bolt $A$, a brass tube $B$ and a nut $C$. The nut is turned so that it just secures the tube, and then is tightened one extra turn. Determine the resulting force $F_s$ in the steel bolt. The initial length of the tube is $L = 131$ $mm$, and the screw pitch is $1$ $mm$ (the nut moves $1$ $mm$ along the bolt for each turn). For the steel bolt, $E_s = 200$ $GPa$, $A_s = 32$ $mm^2$. For the brass tube, $E_b = 100$ $GPa$, $A_b = 96$ $mm^2$.

$F_s=$ $kN$