Consider the function $y = \ln\!\left(x^{2}+1\right)$.

$\displaystyle \frac{dy}{dx} =$

Find the point on the graph of $y = \ln\!\left(x^{2}+1\right)$ where the tangent line is perpendicular to the line $y = 5-x$. You should report your answer in the form $(x,y)$.

$(x,y) =$