Shark Inc. has determined that demand for its newest netbook model is given by $\ln{q}-3 \ln{p} + 0.002 p = 7$, where q is the number of netbooks Shark can sell at a price of p dollars per unit. Shark has determined that this model is valid for prices $p \ge 100$. You may find it useful in this problem to know that elasticity of demand is defined to be $E(p) = \frac{dq}{dp}\frac{p}{q}$

Find $E(p) =$
Your answer should only be in terms of $p$.

What price will maximize revenue. If the price is less than 100, write 'NA'.
$p =$