Consider the function $f(x) = \frac{1}{x^2}$.
Let $T_n$ be the $n^{th}$ degree Taylor approximation of $f(1.02)$ about $x = 1$.

Find:
$T_{1} =$
$T_{2} =$
Use 4 decimal places in your answer, but make sure you carry all decimals when preforming calculations

$T_{2}$ is an (over/under) estimate of $f(1.02)$.

If $R_{2}$ is the remainder given by the Lagrange Remainder Formula:
$\left|R_{2}\right| \le$