By definition, $e$ is the number such that $$\displaystyle\displaystyle\lim_{h \to 0} \frac{e^h-1}{h}=1.$$ Use a calculator to estimate the values of the limits (rounded to the nearest hundredth): $$\displaystyle A=\displaystyle\lim_{h \to 0} \frac{{2.7}^h-1}{h} \quad \text{and} \quad \displaystyle B=\displaystyle\lim_{h \to 0} \frac{{2.8}^h-1}{h}.$$ NOTE: From this, you should conclude that $e$ is somewhere between $2.7$ and $2.8$.

$A=$
$B=$