Use the table below to estimate the value of $h'(.5)$, where $h(x)=f(g(x))$ to the nearest tenth. To estimate the appropriate derivatives, use the average of the two second slopes near the point in question (if approximating a derivative at $x=.1$, do the secant slopes on $[0,.1]$ and $[.1,.2]$, and then average them).

$$\begin{array}{|c|c|c|} \hline x & f(x) & g(x) \\ \hline 0 & 12.6 & .58 \\ .1 & 14.8 & .40 \\ .2 & 18.4 & .37 \\ .3 & 23.0 & .26 \\ .4 & 25.9 & .17 \\ .5 & 27.5 & .10 \\ .6 & 29.1 & .05 \\ \hline \end{array}$$

$h'(.5) =$