The function $g$ is a twice differentiable function. Find $f''$ in terms of $g$, $g'$, and $g''$ if $f(x)=g(\sqrt{x})$.
Below, use "g" for $g(\sqrt{x})$, "h" for $g'(\sqrt{x})$, and "k" for $g''(\sqrt{x})$.

$f'(x) =$