A log 10 meters long is cut at 1-meter intervals and its cross-sectional areas $A$ (at a distance $x$ from the end of the log) are listed in the table. $$\begin{array}{|c|c|}\hline x\ (\textrm{m}) & A\ (\textrm{m}^2) \\ \hline 0 & 0.68 \\ \hline 1 & 0.65 \\ \hline 2 & 0.64 \\ \hline 3 & 0.61 \\ \hline 4 & 0.58 \\ \hline 5 & 0.59 \\ \hline 6 & 0.53 \\ \hline 7 & 0.55 \\ \hline 8 & 0.52 \\ \hline 9 & 0.50 \\ \hline 10 & 0.48 \\ \hline \end{array}$$

Use the Midpoint Rule with $n = 5$ to estimate the volume of the log.

Volume $\approx$ cubic meters