If $\displaystyle \int_{-2}^{4}\! f(x) \, dx = -4$, $\displaystyle \int_{2}^{4}\! f(x) \, dx = 8,$ and $\displaystyle \int_{-2}^{4}\! g(x) \, dx = 8,$ find the following integrals.

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1. $\displaystyle \int_{-2}^{2}\! f(x) \, dx =$

2. $\displaystyle \int_{-2}^{4}\! [g(x) + 6] \, dx =$

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