Past experience indicates that the monthly long-distance telephone bill is normally distributed with a mean of 18.81 dollars and a standard deviation of 3.85 dollars. After an advertising campaign aimed at increasing long-distance telephone usage, a random sample of 25 household's bills was taken. The data (in dollars) is below.

$$\begin{array}{cccccccccccccccccccccccc} 21.25 & 14.87 & 24.8 & 27.56 & 20.62 & 15.42 & 23.67 \\ 18.72 & 21.48 & 18.45 & 23.79 & 24.71 & 21.28 & 15.23 \\ 20.63 & 15.57 & 20.25 & 25.67 & 26.14 & 26.06 & 17.89 \\ 23.74 & 23.85 & 21.17 & 21.76 \\ \end{array}$$

Can we conclude at the 5% significance level that the campaign was successful? Fill in the requested information below.

A. The value of the standardized test statistic:

Note: For the next part, your answer should use interval notation. An answer of the form $(-\infty, a)$ is expressed (-infty, a), an answer of the form $(b, \infty)$ is expressed (b, infty), and an answer of the form $(-\infty, a) \cup (b, \infty)$ is expressed (-infty, a)U(b, infty).

B. The rejection region for the standardized test statistic:

C. The p-value is

D. Your decision for the hypothesis test:

A. Reject $H_1$.
B. Do Not Reject $H_1$.
C. Reject $H_0$.
D. Do Not Reject $H_0$.