A particle moves along a straight line and its position at time $t$ is given by $s(t)= 2t^3 - 21 t^2 + 36 t$ where s is measured in feet and t in seconds.
Find the velocity (in ft/sec) of the particle at time $t=0$:
The particle stops moving (i.e. is in a rest) twice, once when $t=A$ and again when $t=B$ where $A < B$. $A$ is
and $B$ is
What is the position of the particle at time $14$?
Finally, what is the TOTAL distance the particle travels between time $0$ and time $14$?