Let $$A=\left(\begin{array}{cc} -3 & 6 \cr 3 & -8 \cr 9 & 6 \end{array}\right).$$ Then $$-A=\left(\begin{array}{cc} a_{11} & a_{12} \cr a_{21} & a_{22} \cr a_{31} & a_{32} \end{array}\right)$$ where $a_{11}=$ , $a_{12}=$ , $a_{21}=$ , $a_{22}=$ , $a_{31}=$ , $a_{32}=$ , $$3 A=\left(\begin{array}{cc} b_{11} & b_{12} \cr b_{21} & b_{22} \cr b_{31} & b_{32} \end{array}\right)$$ where $b_{11}=$ , $b_{12}=$ , $b_{21}=$ , $b_{22}=$ , $b_{31}=$ , $b_{32}=$ , and $$A^T=\left(\begin{array}{ccc} c_{11} & c_{12} & c_{13} \cr c_{21} & c_{22} & c_{23} \end{array}\right)$$ where $c_{11}=$ , $c_{12}=$ , $c_{13}=$ , $c_{21}=$ , $c_{22}=$ , $c_{23}=$ .