The altitude of a triangle is increasing at a rate of $1.0$ centimeters/minute while the area of the triangle is increasing at a rate of $4.5$ square centimeters/minute. At what rate is the base of the triangle changing when the altitude is $8.0$ centimeters and the area is $92.0$ square centimeters?
Your answer:
Note: The area $A$ of a triangle with base $b$ and height $h$ is given by $$A = \frac{1}{2}bh.$$