Suppose you want to solve the equation $$f(x) = x^2-\cos x = 0$$ using Newton's method. Newton's method starts with an initial approximation $x_0$ and then computes a sequence of approximations $x_1$, $x_2$, $x_3$, $\ldots$ via the formula $$x_{k+1} = g(x_k), \quad k = 0,1,2,\ldots$$ where $$g(x) = x - \frac{f(x)}{f'(x)}.$$ For the function defined above, $g(x) =$ .
Letting $$x_0= 0.6$$ you obtain
$x_1$ = ,
$x_2$ = , and
$x_3$ = .