Solve the following system: $$\begin{array}{rcrcrcl} x &+& y &+& z &=& -5 \\ 2x &-& y &+& 3z &=& -16 \\ 3x &+& y &-& 4z &=& 4 \\ \end{array}$$ Keep track of your calculations, because in the next problem you will have the same system, except that the right hand side is different.
The solution is $x =$ , $y =$ , $z =$ .