Let $$p(x) = 6x^3-5x^2-2x+1.$$ It is easy to check that $p(1)=0$, i.e., $1$ is a zero of $p$. $p$ has two more real zeros. The smaller is $x=$ , and the larger is $x=$ .
Hint: Use synthetic division to divide $p$ by $x-1$, and find the zeros of the quadratic quotient.