The relationship between a number of decibels $\beta$ and the intensity of a sound $I$ (in watts per square meter) is $$\beta = 10 \log_{10}\left(\frac{I}{10^{-12}}\right).$$
The number of decibels for a sound with an intensity of $10^{-6}$ watts per square meter is .
A sound with ten times that intensity has decibels.
In general, a sound with ten times the intensity of a sound with $n$ decibels has decibels.
Hint: It may help to use the properties of logarithms to rewrite the equation given in this problem.