$\frac{1}{x^2+9 x +14} +\frac{1}{x+2} =($ $)/($ $)$.
$\frac{1}{x^2+9 x +14}-\frac{1}{x+2} =($ $)/($ $)$.
$\frac{1}{x^2+9 x +14} \times \frac{1}{x+2} =($ $)/($ $)$.
$\frac{1}{x^2+9 x +14} \div \frac{1}{x+2} =($ $)/($ $)$.
Hint: Factor the quadratic denominator.