(Note that most of your answers are algebraic expressions involving $t$.)
A car starts on a trip and travels at a speed of 55 mph. Two hours later, a second car starts on the same trip and travels at a speed of 65 mph.
When the second car has been on the road for $t$ hours, the first car has traveled miles and the second car has traveled miles.
At time $t$ the distance between the first car and the second car is miles.
The ratio of the distance the second car has traveled and the distance the first car has traveled is .
The second car catches up with the first car hours after the departure of the first car. (Those are some determined drivers!)
Hint: If you are having trouble with the last part of this problem reread the question carefully. It's not my wording, and if it's any consolation, I got hung up on it myself at first.