Solve the system using substitution $$\left\{ \begin{array}{r@{}r@{}r@{}r} x & -3 y & = & 0 \cr 6 x & - y^2 & = & 0 \end{array} \right.$$ There are two solutions $(x_1,y_1), (x_2,y_2)$ for $x_1 < x_2$. $x_1 =$
$y_1=$
$x_2 =$
$y_2=$