The equation $$|x-1| + |x-2| = 3.$$ has two solutions.
Enter the smaller here and the larger here
Hint: One way to answer this question is to write down the four possible cases for the two absolute values. A more sophisticated approach is to observe that the first absolute value is zero when $x=1$ and the second when $x=2$. Ask what happens in each of these cases: $x\leq 1$, $1\leq x \leq 2$, and $x\geq 2$.