Given $$f''(x) = 2x + 1$$ and $f'( -3) =0$ and $f( -3)=6$.

Hint: start with integrating the second derivative function, and use the "fixed point" $f'( -3) =0$. Then solve for C, giving you the first derivative function. Now integrate this function, and use the second fixed point given to solve the second part of the problem.

Find $f'(x) =$
and find $f( 4) =$