In this problem you are asked to convert radians to degrees.
$6\pi\hbox{rad} =$ ${}^\circ.$
$-0.7\hbox{rad} =$ ${}^\circ.$
$\left(\sqrt{2}\right)\pi\hbox{rad} =$ ${}^\circ.$
Hint: Everything follows from the fact that $$360^\circ = 2\pi \hbox{~rad}.$$