Suppose $$\sin(u) = \frac{3}{5}$$ and $\cos(u)$ is negative. Then
$\cos(u) =$
$\tan(u) =$
$\sin(-u) =$
$\cos(-u) =$
$\tan(-u) =$
$\sin\left(u+\pi\right) =$
$\cos\left(u+\pi\right) =$
$\tan\left(u+\pi\right) =$
$\sin\left(u+\frac{\pi}{2}\right) =$
$\cos\left(u+\frac{\pi}{2}\right) =$
$\tan\left(u+\frac{\pi}{2}\right) =$