In this problem you need to get everything right to get credit. The idea is that you go over everything an think about the whole context. Use the preceding problem as a guide.
Suppose $$\sin(u) = \frac{12}{13}$$ and $\cos(u)$ is negative. Note that $\cos u$ is a rational number. I recommend you enter fractions below.
$\cos(u) =$
$\tan(u) =$
$\sin(-u) =$
$\cos(-u) =$
$\tan(-u) =$
$\sin\left(u+\pi\right) =$
$\cos\left(u+\pi\right) =$
$\tan\left(u+\pi\right) =$
$\sin\left(u+\frac{\pi}{2}\right) =$
$\cos\left(u+\frac{\pi}{2}\right) =$
$\tan\left(u+\frac{\pi}{2}\right) =$