Evaluate the limits. $$f(x) = \begin{cases} 3 x^2 - 5 & x < -1 \\ 3 x^3 + 5 & -1 \leq x \leq 1 \\ 3 x^2 + 5 & x > 1 \end{cases}$$ Enter DNE if the limit does not exist.

1. $\displaystyle{ \lim_{x \to -1^-} f(x) }$ =
2. $\displaystyle{ \lim_{x \to -1^+} f(x) }$ =
3. $\displaystyle{ \lim_{x \to -1} f(x) }$ =
4. $\displaystyle{ f(-1) }$ =
5. $\displaystyle{ \lim_{x \to 1^-} f(x) }$ =
6. $\displaystyle{ \lim_{x \to 1^+} f(x) }$ =
7. $\displaystyle{ \lim_{x \to 1} f(x) }$ =
8. $\displaystyle{ f(1) }$ =