\displaystyle{ \int_0^1 \left({-3x+9}\right) \, dx } =\displaystyle{ \int_0^{{3}} \left({-3x+9}\right) \, dx } =\displaystyle{ \int_0^{{4}} \left({-3x+9}\right) \, dx } =\displaystyle{ \int_1^{{6}} \left({-3x+9}\right) \, dx } =\displaystyle{ \int_0^1 \left({-6x+18}\right) \, dx } =

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