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Evaluate the definite integrals

$\displaystyle{\int_{{1}}^{3} \frac{1}{x} \, dx = }$

$\displaystyle{\int_{{1}}^{6} \frac{1}{x^2} \, dx = }$

$\displaystyle{\int_{{1}}^{3} \frac{1}{x^{6}} \, dx = }$

$\displaystyle{\int_{{0}}^{9} x^2 \, dx = }$

$\displaystyle{\int_{{0}}^{{1}} x^{60} \, dx = }$

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