For a plane curve $\mathbf{r}(t)=\langle x(t),y(t)\rangle$, $$\kappa(t)=\frac{|x'(t)y''(t)-x''(t)y'(t)|}{(x'(t)^2+y'(t)^2)^{3/2}}.$$ Use this equation to compute the curvature at the given point. $$\mathbf{r}(t)=\langle -3t^{2},t^{5}\rangle, t=5.$$

$\kappa(5)=$