Fill in the table and guess the value of the limit:
$\lim\limits_{x \to 2} f(x)$, where $f(x)= \frac {x^3 - 8} {x^2 - 4}$

$x$	$f(x)$	$x$	$f(x)$
2.002	$\qquad \qquad$	1.998	$\qquad \qquad$
2.001	$\qquad \qquad$	1.999	$\qquad \qquad$
2.0005	$\qquad \qquad$	1.9995	$\qquad \qquad$
2.0001	$\qquad \qquad$	1.9999	$\qquad \qquad$

The limit as $x \to 2$ is