Find the partial fraction decomposition for the rational function:

$\frac{0 x^2 - 1 x - 27}{(x - 3)\left(x^2+6\right)}=$
A. $\frac{2}{x - 3}+\frac{2 x+5}{x^2+6}$
B. $\frac{ + 2}{x - 3}+\frac{-2 x+2}{x^2+6}$
C. $\frac{-2}{x - 3}+\frac{2 x+5}{x^2+6}$
D. $\frac{-2}{x - 3}+\frac{2 x-5}{x^2+6}$