Find $\frac{dy}{dx}$ and $\frac{d^2 y}{dx^2}$ at the given point without eliminating the parameter.

$\small{x = \frac{1}{2} t^{2}+2}$, $\small{y = \frac{1}{4}t^{4}+8 t}$, $\small{t = 3}$.

$\frac{dy}{dx} =$ $\frac{d^2y}{dx^2} =$