For $\small{f(x) = 2x^{3}+1}$, find $\small{f\;'(x)}$ using the definition $\small{f\;'(x) = \displaystyle\lim_{h\rightarrow 0}} \large{\frac{f(x + h) - f(x)}{h}}$.

$\small{f\;'(x) =}$

Using this, find the tangent line to the graph of $\small{y = 2x^{3}+1}$ at $\small{x = -2}$. Enter all values as integers, or fractions in lowest terms.

$\small{y = }$