Set up, but do not evaluate, the integral for the surface area of the solid obtained by rotating the curve $y=3xe^{-8x}$ on the interval $1 \le x \le 6$ about the line $x=-1$.

$\displaystyle \int$

Set up, but do not evaluate, the integral for the surface area of the solid obtained by rotating the curve $y=3xe^{-8x}$ on the interval $1 \le x \le 6$ about the line $y=-1$.

$\displaystyle \int$

Note: Don't forget the differentials on the integrands.