Set up, but do not evaluate, the integral for the area of the surface obtained by rotating the curve $y \sin y - \sqrt[3]{x}=0$ between the points $(0,0)$ and $(\pi^{3}/8, \pi/2)$ about the line $x=4$.

$\displaystyle \int$

Set up, but do not evaluate, the integral for the area of the surface obtained by rotating the curve $y \sin y - \sqrt[3]{x}=0$ between the points $(0,0)$ and $(\pi^{3}/8, \pi/2)$ about the line $y=-5$.

$\displaystyle \int$

Note: Don't forget the differentials on the integrands.