Let $\displaystyle \int_{-6}^{3} f(x)\, dx =7, \ \int_{-6}^{-3} f(x)\, dx=3, \ \int_{0}^{3} f(x)\, dx =8$.

Find $\displaystyle \int_{-3}^{0} f(x)\, dx=$

and $\displaystyle \int_{0}^{-3} 7 f(x)- 3 \, dx=$